$f\left(x\right)=\left(x+2\right)\left(2x^2-3\right)$
$\lim_{x\to1}\left(\frac{3^x-x^2-x-1}{x^2-1}\right)$
$\frac{y^3-6y+5}{y^2+3y-2}$
$\left(-2x+3y-2\right)+7\left(3x-5y-1\right)-3\left(-4y-8\right)$
$3x+2iy=6+10i$
$2025-18$
$3a\cdot1a$
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