$v^2+8v+16$
$\frac{\sec\left(x\right)-\cos\left(x\right)}{\sec\left(a\right)}$
$\left(6x^4-4\right)^2$
$\left(-12\right)\:\left(2\:+\:2\:+\:4\:-\:10\right)$
$5x+3x-9$
$\frac{90}{18}$
$\int\left(x^3\left(2x^4+1\right)^3\right)dx$
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