$-2x^2+3x+3$
$.000258+3.002+89.568$
$4x^2+12xy+8y^2$
$\left(4x^8-16y^2\right)$
$\lim_{x\to0}\:\frac{\left(-x-3\right)^2-9}{2x}$
$\left(r+t\right)^2$
$\frac{-x^2+4x+9}{-x^2-16}$
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