$\int_0^1\left(\left(\frac{\left(x^2-1\right)}{x^2\left(x-5\right)}\right)\right)dx$
$\int6x^{-\frac{4}{5}}+2x^{\frac{7}{5}}dx$
$\:972,4-39,67$
$-5-\left(-6\right)\left(7\right)$
$ty'+t^2+ty-y=0$
$\sin\left(bt\right)^2$
$40\cdot15$
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