$\int\frac{16}{4-x^2}dx$
$\left(1+tan^2u\right)\left(1-sen^2u\right)=1$
$\left(a-2\right)\left(a-10\right)$
$25x^2-80x$
$+3-\left(+4\right)\cdot\left(-2\right)$
$\int_{3\pi}^{6\pi}\theta\:d\theta\:$
$3x+y-2+y'.\left(x-1\right)=0$
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