$\left(m\:+\:\frac{5}{4}\right)^3$
$4\cdot\left(nx\right)\cdot x^n$
$\frac{\left(3x-4y^2\right)^8}{225}-t^{4n}$
$5a+2b=10$
$\sec^2\left(x\right)-\tan\left(x\right)-3$
$-27\cdot\left(-5\right)-216$
$\frac{d}{dx}y^5+3y^2-2x^4=-4$
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