$\int\frac{x^4}{x^2+16}dx$
$\left(\frac{2}{5}z+5\right)\left(\frac{1}{5}z+1\right)\:$
$\left(5y^2-6v^2\right)^2$
$\int x^2\sec^3\left(x^3\right)dx$
$-343-\left(-23\right)$
$\left(7y^2+4\right)^2$
$7x-4=5x+6$
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