$d x + e ^ { x + y } d y = 0$
$\left(\:8a\:+\:b\right)^3$
$3x^2-5x+8-x^2-6$
$y=\frac{x^3-1}{x^2+1}$
$\lim_{x\to\infty}\:\left(x^3-2\right)$
$\frac{\left(x^3-8x-5\right)}{x+3}$
$2x+3-x^2-2x+x^2$
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