$\lim_{x\to\infty}\:\frac{2x^2-5x+4}{3+5x^3}$
$6+x-3\:x^2$
$-2\:+\:4\:cos2\:\theta\:=\:1$
$x^2-64=0$
$\int-\frac{5}{\left(x^2+5\right)^{\frac{3}{2}}}dx$
$\lim_{t\to1}\left(\frac{t^3-6t+5}{t-1}\right)$
$\int10sen^4\left(4x\right)dx$
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