$\sqrt{16x^3}y$
$-5x^3+4x+3x^2-2x+5x^3$
$\int\:6x\left(4x^2-9\right)^2dx$
$\left(3x-\frac{1}{2}y\right)^5$
$4\sin\left(3x\right)=2$
$\frac{3x^4-5x^2+x-3}{x^2+1}$
$-x\:+\:10\:-\:8x\:+\:2x\:=\:17$
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