$\int sec^2x\left(1+tanx\right)^{\frac{2}{3}}dx$

$x^2-2x+1+x-1$

$\left(2a^2-5b^3\right)^3$

$64x^6+16x^{24}+x^2$

$\int_0^{\frac{\sqrt{2}}{4}}\left(\frac{2}{\sqrt{1-4t^2}}\right)dt$

$4\:cos^2\left(x\right)-13\:cos\left(x\right)-12=0$

$\frac{\sec\left(a\right)^2}{1+cot^2a}=\tan\left(a\right)^2$