$1\:+2x\:-\:1$
$\lim_{x\to\infty}\left(\frac{x-\frac{4}{3}}{\sin\left(\frac{1}{x}\right)}\right)$
$x-7<-9x+13$
$\frac{5x^4-3x^3+4x-8}{x-2}$
$\frac{1}{2x^2-9x-5}$
$\:|-8|\:+\:|12|\:-\:|-7|$
$\left(2x^2-9\right)\left(2x^2\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!