$\lim_{x\to0}\left(\frac{3x+2x^2}{5x+6}\right)$
$\frac{1+\cos x}{cot\:x}=\tan x+sin\:x$
$\left(\left(3a\right)\left(4b\right)\right)^{\frac{1}{3}}$
$x+y=10$
$\lim_{x\to\infty}\left(\frac{\sqrt{x+5}}{5+\sqrt{x}}\right)$
$m.\left(e+b\right)=e.s+b.k$
$4x+6=-x+21$
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