$5x^2-3x-6$
$\frac{-3}{4}.\frac{4}{1}$
$\log_{10}\left(10^x\right)=7$
$2\left(2x\right)\left(-6\right)$
$18\:+\:\left[\:13\:+\:4\:-\:\left(\:5\:-\:7\:\right)\:+\:6\:\right]\:$
$-48m\:-\:24m\:-\:36m\:+\:6m$
$-3x-2y^{15}$
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