$6x^2+3x=0$
$x^2-3x+350$
$\frac{64m^6-729m^6}{2m-3n}$
$x\:5\:y\:.\:4nx\:3$
$10x^2+6x$
$\sqrt[5]{-\frac{1}{32}}\cdot\frac{3}{2}$
$\lim_{x\to\infty}\left(1-\frac{7}{x-3}\right)^{x-3}$
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