$\frac{x^3}{3}\left(y+2z\right)$

$\left(2^8+1\right)$

$1+\tan^2\left(a\right)=\frac{1}{\cos^2\left(a\right)}$

$\frac{dy}{dx}=9y\left(4-y\right)$

$-\left(a^2b^2\right)^2-\left(ab\right)^2-1$

$\int\left(\frac{2}{x\left(-1+\ln\left(4x\right)\right)}\right)dx$

$\frac{-2x+18}{x^3+6x^2+9x}$