$\left(x^2+\sqrt{5}\right)^3$
$3\left(x+1\right)\left(x-2\right)$
$4\cdot5+4\cdot7$
$2\:-\:3\:-\:-\:8\:-\:1\:+\:4$
$-3a-4b$
$\frac{1}{x-1}>1$
$\int\left(\frac{\sqrt{\left(x^2+9\right)}}{x^2}\right)dx$
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