$8-1000$
$\left(36x^3y^7z^4\right):\:\left(12x^2y^2\right)$
$\int\left(x+2\right)\cdot e^{\left(x^2\right)+4x}d\left(x\right)$
$\left(3c-1\right)^2$
$2x^3+6x-2$
$\frac{8x^5+4x^3+3x^2+7x+16}{2x^3+x^2+3}$
$2x^2-2x=12$
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