$4^4x^{3n}y^2$
$\frac{x^2-6x+12}{x-4}$
$\sqrt[3]{\frac{x\left(x-4\right)}{x^2+8}}$
$x^6-\frac{1}{16}x^2$
$\sqrt{3^2+3^2}$
$-\left(-6.3d-4f+1.8\right)$
$\frac{\left(2x^3\right)^2\left(3y^4\right)^3}{12x^4y^5}-4x^2y^7$
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