$\frac{dx}{dt}=-0,06$
$\left(4x\right)\left(3xy\right)$
$\int\left(\frac{1}{\sqrt{4+196x^2}}\right)dx$
$-8a^x+13a^x$
$\frac{x+2}{3}<x-\frac{1}{2}$
$\left(2\sqrt[4]{3}\right)^2$
$\left(-4\right)^2-4\left(3\right)\left(-3\right)$
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