$-2\left(a-b\right)^3$
$\left(2x-3\right)^2-5=0$
$sen\left(2x\right)+2cos^2x=2$
$\left(a-2\right)\left(a+2\right)\left(a^4+4a^2+16\right)+64$
$\frac{4}{6}\cdot0.4$
$\int_{10}^{\infty}\left(\frac{lnx}{x}\right)dx$
$x+2+-4x^2+16x+6$
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