$\frac{1}{5}\left(x+2y\right)+\frac{1}{10}y=\frac{7}{10}\left(x+1\right)-\frac{1}{2}-\frac{2}{5}x\:$

$\left(-8\right)\left(5\right)\left(-8\right)\left(2\right)$

$\tan\left(x\right)-\csc\left(x\right)\sin\left(x\right)\left(1-\cos^2\left(x\right)\right)$

$\int_2^5\left(6x^2+4x\right)dx$

$16\sec^2\left(x\right)-25=0$

$\int cosx\left(1+sin^2x\right)dx$

$4x^2+4\cdot y+2y^2$