$\int\frac{x}{x^2+3x}\:dx$
$\left(2x+3\right)\left(2x^2-3x\right)$
$\left(2xy+x^2\right)y'=x^2+2y^2$
$\left(3x^{3-2xy}\right)^6$
$\frac{3.-3^2}{4}+\frac{4n^2}{m}$
$\frac{dy}{dx}=x\sqrt{1-x^2}$
$8x-15x-30x+79-51x=53x-93+31x$
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