$b\left(4+8t+4t^2\:\right)$
$\frac{dy}{dx}=\frac{y}{x}\:+\:x$
$-7b\:-\:19\:-\:17b\:-\:14$
$\int\cos\left(2x+2\right)dx$
$12a\:+\:20b$
$4-4\left(1-y\right)+\left(1-y\right)^2$
$\left(x+6\right)\left(x-6\right)-\left(x+6\right)^2$
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