$\int\left(\sec^2\left(\frac{1}{3}x\right)\right)dx$
$xy^2dx+3x^3y^2dy=0$
$\left(x+1\right)2-9y^2$
$\frac{1-\sec\left(x\right)}{1-\cos\left(x\right)}=-\sec\left(x\right)$
$\lim_{z\to2}\left(\sqrt{\frac{4x^3-2}{2x+1}}\right)$
$m^2+20m+81$
$-6m^2n\left(m^2n\right)$
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