$6x^2+5\:x+1$
$cos2x=-cosx$
$3\cdot\left(5x-1\right)+\left(x-1\right)\left(x+1\right)-\left(x-1\right)^2$
$1o-\left(-14\right)$
$\int\left(2x^2+3\right)^2\cdot5xdx$
$\frac{dy}{dt}=23$
$4a+10b+4c$
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