$\frac{\left(2cd^4\right)^4}{\left(2c^2d^3\right)^2}$

$\lim_{x\to\frac{1}{2}}\left(\frac{6x^2-x-1}{4x^2-4x-3}\right)$

$\frac{dy}{dx}=\frac{-1y}{2}+\frac{3}{2}$

$\left(x+4\right)\:y\:\left(x-2\right)\:$

$8xy-17xy+6xy-4xy$

$-0,25-3,6$

$\frac{dy}{dx}=2sin\left(x+y\right)$