$y=y'+x$
$\frac{dy}{dx}=2y+3y^2$
$\cot x-\cos x$
$x^2+\frac{5}{4}x$
$10a+3b-4c+d-4a+2b$
$\frac{dy}{dx}=e^x\cdot e^{-3y},y\left(0\right)=2$
$\left(x^3+3x^2\right)^2$
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