$\frac{d}{dx}\frac{1}{e^{3x}}$

$\frac{\sec\left(x\right)\left(\sec\left(x\right)+1\right)\left(\sec\left(x\right)-1\right)}{\sec\left(x\right)-\frac{1}{\sec\left(x\right)}}=\sec^2\left(x\right)$

$\int\left(\frac{x^2}{x^2-6x+3}\right)dx$

$\frac{4x^2+16y^2}{3x-4y}$

$10\left(d-5\right)^2^a-\left(c+3\right)^3-\left(b+6\right)^5c^2;\:a=4;\:b=-7;\:c=-1;\:d=6$

$\left(a^4+8\right)\left(-9a^4-1\right)$

$\left(9a-11b+5c+8d\right)-\left(a+8b-7c-2d\right)$