$\int\frac{\left(2x+7\right)}{\left(x^2+2x+5\right)}dx$

$\left(x-1\right)\left(x-2\right)\left(x-4\right)\left(x-8\right)$

$6a+11b+3a+8b$

$4\sin\left(x\right)-3=-5$

$\frac{\left(\sec\left(x\right)-\tan\left(x\right)\right)\left(\sec\left(x\right)+\tan\left(x\right)\right)}{\csc\left(x\right)}=\sin\left(x\right)$

$\int_0^8\left(\frac{20x^2-5x+13}{\left(8-x\right)^2}\right)dx$

$5\sqrt{\frac{7}{25}}$