$\lim_{x\to\infty}\left(\frac{1}{6x+3}\right)$
$\frac{dx}{dt}\:x=\left(t^2\right)e^t$
$\left(12a\:+15b\right)^2$
$-2\:=\:x^4y^5$
$3^{3x-2}=81$
$\int\frac{2x+3}{\left(x^2+3x+1\right)^2}dx$
$x^5-x^3$
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