$\int\left(\frac{1}{3}\tan\left(3x\right)\right)dx$
$5x+4+8x$
$x^3+y^3=8$
$\left(t-ln\left(y\right)\right)y'=y$
$\int\:\frac{x+3}{x^4+9x^2}dx$
$-1-\frac{y}{1+x+2y}$
$100-12+5-11+12-13+8-11+4-15+6-13-9+8$
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