$\frac{2x^3-5x^2-1}{x^2-4x+5}$
$\left(2\right)\left(4x^2\right)\left(x\right)$
$12x^3-8x+340$
$\frac{d}{dx}2x^3-3x^2y+2xy^2-y^3=0$
$9x^8-30x^4+25$
$27-\left(-10\right)$
$\left(9x^2-4x+1\right)\left(6x^3-5x\right)$
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