$\frac{32a^2-243}{2a^2-3}$
$-9\cdot\left(\frac{0}{-3}\right)$
$\lim_{x\to\infty}\frac{0.15x}{x^2+3}$
$\frac{\sin^4\left(x\right)}{\left(1-\cos^2\left(x\right)\right)}$
$\frac{dy}{dx}=-3.3$
$169-4x^6-12x^3-9$
$-3^2+5$
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