$\left(6x^3y^4\right)^2$
$\left(a-\frac{1}{4}\right)^3$
$-11\cdot22$
$\left(3x-y\right)\left(9x^2+3xy+4y^2\right)$
$\left(x-2\right)\left(x+2\right)+\left(x-3\right)^2$
$\lim_{x\to0}\left(\frac{\sin\left(x^2\right)}{x^2}\right)$
$\frac{8}{x+9}=\frac{x+9}{18}$
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