$x^4+2x^2+6yx3$
$\frac{1}{3}\left(9x-24\right)+x$
$2x\le-2$
$\frac{x}{4}>\frac{3}{5}$
$\frac{dy}{dx}=\frac{1}{3y^2+6}$
$\frac{\left(\frac{i}{2}\right)}{\left(x+1+i\right)}+\frac{\left(-\frac{i}{2}\right)}{\left(x+1-i\right)}$
$4x^{\left(2\right)}<=20x-40$
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