$\frac{k}{-8}=20$
$\left(4v\:-\:\:6\right)^2$
$\left(x-2\right)^2\cdot3$
$\int\left(\frac{6x^2+12}{x-2}\right)dx$
$x^2+2x<x+2$
$-5x+4y=-58$
$\frac{d}{dx}\:c=0$
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