$\left(\sqrt{6}x\:-\:15\:\right)\:\left(\:\:\sqrt{6}x\:+\:11\:\right)$
$\left(25x^2-10\right)\left(25x^2+10\right)$
$\frac{4y}{x+1}-3y=\arctan\left(x\right)$
$\frac{dy}{dx}=0.75x$
$a^2+2a-48$
$\frac{dy}{dx}\left(y^2+2y=x\right)$
$2sen\:=1$
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