$y=\ln\left(\frac{\left(2x-3\right)^3}{4x}\right)$
$-6-8+15-7-4+3-2+9-14$
$-\sin x=\cos x$
$\cot\left(x\right)^2-\cot\left(x\right)+\csc\left(x\right)^2=4$
$\lim_{x\to0}\left(x^2\cdot e^{-x}\right)$
$3y=\frac{dy}{dx}-6x^3$
$m^2+71mn-14m^2-65mn+m^3-m^2-1$
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