$\int6\tan^3\left(x\right)dx$
$\frac{1}{3^2+3}>\frac{1}{3^2-3}-\frac{1}{3^2-3}$
$4x-2x^2=1$
$7x-1-7xy+y$
$\frac{d}{dx}\left(e^{2x}\cdot\left(x^2+5x-1\right)\right)$
$4x-4<40$
$x^2-6x>-9$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!