$24ab;\:a=1;\:b=2$
$\left(2x+y\right)y'=1$
$\sqrt{36\cdot4\cdot9\cdot c^2\cdot y^5}$
$4\:\:6\:\:-1\:\:-4\:3\:4$
$\frac{3a^2}{6ab}$
$\frac{d^2}{dx^2}\left(2xy^2\right)$
$\frac{e^{-1}}{a^{-3}}$
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