$\int e^bdb$
$\tan\left(2x\right)=\frac{24}{7}$
$4\left(2x^3-3x+2\right)$
$-8-1-2+4-1+3-7$
$\frac{x}{x+3}+\frac{3}{x^2+7x+12}=\frac{5}{x+4}$
$5^2\left(6\right)+9$
$\int\frac{19}{x^2\sqrt{x^2+81}}dx$
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