$8\left(\frac{a^8+b^8}{\left(ab\right)^4}\right)$
$-47\left(21\right)$
$4+7b^2+2+2b^2+3b$
$y^{'\:}=\frac{x^2}{\left(y^{\:3}-2y\right)}$
$\left(2x\:+\:2y\right)\left(2x\:-\:2y\right)\:$
$x^3+40x^2$
$y=\frac{t^2}{2}-\sqrt{1-t^2}$
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