$-\frac{2}{x-3}=\frac{x}{x-6}$
$9^{-1}\cdot9^0$
$dx=-e^{3x}dy$
$\left(2x^2-4xy+5y^2\right)\left(2x^2-y^2\right)$
$\int x^4\left(x^2-3\right)^{\left(\frac{1}{2}\right)}dx$
$\frac{dy}{dx}=\left(2\cdot x^2+4\right)\cdot y+3\cdot x^2+6$
$x=y^2-2y$
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