$\int\frac{1}{16-9\cdot x^2}dx$
$\left(\sin\pi x+\cos\pi x\right)^9=25$
$\int x\cdot\sqrt{x+2}$
$\int\frac{8+3x-x^2}{\left(2x-3\right)\left(x+2\right)^2}dx$
$\frac{dy}{dx}=x^4-2x^3+5x^2-2x$
$-3+6\cdot5+6\cdot2$
$4\left(x-5\right)<8-3\left(x+2\right)$
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