$\int-x^2\left(\frac{1}{2^x}\right)dx$
$4+4x\ge2x+6$
$2x^2+6x=-3$
$2x-3\le1$
$\int3\left(2x^2+1\right)\left(2x^3+3x-2\right)^8dx$
$19\cdot15\cdot150$
$8\left(s+6\right)$
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