$\left(8a^2+3a-4\right)\cdot\left(3a-8\right)$
$x^2-11=0$
$\frac{\cos\left(x\right)^2+\cos\left(x\right)}{\cos\left(x\right)+\sin\left(x\right)}=\cos\left(x\right)$
$\frac{x^2}{3x}$
$f\left(-1\right)=\sqrt{x}^2+1$
$x^3-10x+3$
$\lim_{x\to\infty}\left(\frac{4^x}{x}\right)$
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