$\left(x^3+3y\right)\left(a^2+3b\right)$
$x^2-10=0$
$\frac{9x-8}{x\left(x^2+3\right)^2}$
$\lim_{x\to\infty}\left(\frac{x^3+2}{x^3+x+1}\right)^{x^2}$
$\:-\frac{4+x}{2}=6$
$\frac{x^2-x-2}{x-1}$
$\frac{7x^2-1}{x^2};x=-3$
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