$2x^2-x+4$
$5\left(x+6\right)-5\left(3-2x\right)>10$
$\frac{d}{dx}\left(y=\left(3x-7\right)^4\left(9x^3+2\right)^3\right)$
$\left(2x^3+\frac{7}{3}\right)\left(2x^3-\frac{7}{3}\right)$
$7^8\cdot2^8$
$\left(6x-y+3z\right)^2$
$6\left(-9g+5\right)$
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