$11+\left(7\right)\cdot\left(6-8\right)$
$\frac{z^5}{z^8}$
$2xy^2=4x^3-x^2y^5$
$-5x+2+3$
$12-8-20+3-6-7-9+4-20-23$
$-2x+3\le7$
$7\sqrt{4}^2$
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