$\int\left(\sqrt{9-3x}\right)dx$
$-\left(-1+3\right)^2$
$\frac{a^6b^9-8}{a^2b^3-6c^4}$
$\left(x^2+1\right)\left(3x-5\right)$
$\left(5+\sqrt{2}\right)\left(5-\sqrt{2}\right)=23$
$5x-4>x+8$
$\frac{dy}{dx}\left(x^2y+x^2+y^2=0\right)$
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